4104 is Hardy-Ramanujan's number. Justify.
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Answer:
It is the second positive integer which can be expressed as the sum of two positive cubes in two different ways. The first such number, 1729, is called the "Ramanujan–Hardy number". 4104 is the sum of 4096 + 8 (that is, 163 + 23), and also the sum of 3375 + 729 (that is, 153 + 93).
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Step-by-step explanation:
4104 can be represented as the sum of two cubes two ways.
One way
4104 = 4096 + 8
4104 = 16^3 + 2^3
Second way
4104 = 3375 + 729
4104 = 15^3 + 9^3
Therefore yes it is a Hardy-Ramanujan's number.
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