41st term of an ap where the 1st term of an ap is 25 and common difference is 2
Answers
Answered by
1
Answer:
41st term of A.P. is 105
Step-by-step explanation:
a=25 , d=2 , n=41 , an=?
an=a+(n-1)d
an=25+(41-1)×2
an=25+(40)×2
an=25+80
an=105
∴ 41st term of A.P. is 105
Similar questions