Math, asked by arifkhan91737, 11 months ago

41th term of a series of 81 terms is 10. find the sum of the series

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Answered by agpg1908

11

Answer:

please mark it as a brainliest answer

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Answered by Dedeepya46

4

T41=a+40d=10

S81=81/2[2a+(81−1)d]

=81/2[2a+80d]=81[a+40d]

=81×10

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