Question

41x+53y=135,53x+41y=147

Answer 1

41x+53y=135,53x+41y=147
      53(41x+53y)=    53(135)
     -41(53x+41y)=  - 41(147)
    2173x+2809y=    7155
    -2173x+1681y= - 6027
=1128y                =    1128
       therefore,y=1
              41x+53y=135
            41x+53x1=135
                41x+53=135
                 41x=135-53
                 41x=82
              therefore,x=2

Answer 2

Answer:

Step-by-step explanation:

41x+53y=135------------ (1)

53x+41y=147-------------(2)

by elimination method,

multiply 41 in eq.(1) and multiply 53 in eq.(2),

(41x+53y=135)×41

(53x+41y=147)×53

1681x+2173y=5535

2809x+2173y=7791

- - -

__________________(by subtracting)

-1128x = -2256. (2173y-2173y cancelled)

x = -2256/-1128(- and - is cancelled

x = 2

put the value of x in eq. (2),

53x+41y=147

53×2+41y=147

106+41y=147

41y=147-106

41y=41

y=41/41

y=1

so the value of x=2

y=1

Ans.

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