Question

41x + 53y = 135
53x + 41y = 147
solve using elemination method​

Answer 1

Answer:

Answer:Let, 41x + 53y =135.........(1)

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)Adding equation 1 and 2 we get,

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)Adding equation 1 and 2 we get, 41x + 53y=135

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)Adding equation 1 and 2 we get, 41x + 53y=135 +

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)Adding equation 1 and 2 we get, 41x + 53y=135 + 53x + 41y=147

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)Adding equation 1 and 2 we get, 41x + 53y=135 + 53x + 41y=147_________________

Answer:Let, 41x + 53y =135.........(1)and 53x + 41y =147.........(2)Adding equation 1 and 2 we get, 41x + 53y=135 + 53x + 41y=147_________________ 94x + 94y=282

dividing throughout by 94 we get,

x + y = 3 .......(3)

subtracting equation 1 from 2 we get,

53x + 41y = 147

-

41x + 53y = 135

___________________

_. _. _. ..........( changing signs)

12x - 12y = 12

dividing throughout by 12 we get,

x - y = 1.........(4)

Now adding equation 3 abd 4 we get,

x + y = 3

+

x - y = 1

_________

2x. = 4

x = 4/2

x = 2

substitute x = 2 in equation 3,

2 + y = 3

y = 3 - 2

y = 1

Hope it helps you,