Question

41x + 53y = 135
53x + 41y = 147
solve x and y​

Answer 1

41x+53y=135
53x+41y=147
adding both the equations
94x+94y=282
x+y=3
now subtracting both the eqn's
12x-12y=12
x-y=1
now adding x+y=3 and x-y=1
x=2
substituting x=in x+y=3
2+y=3
y=1

Brainliest please

Answer 2

$94x + 94y = 282 \\ x + y = \frac{282}{94} = 3.........(1 )\\ - 12x + 12y = - 12 \\ - x + y = - 1.........(2) \\ adding(1) \: and \: second \: we \: get \\ 2y = 2 \\ y = 1 \\ put \: the \: value \: of \: y \: in \: 1 \: we \: get \\ x = 2$