41x +53y = 135 and 53x + 41y = 147 sove these linear equations by elimination method, everyone is solving it by substitution but i need elimination method .........
bhoopendra617:
is any body is there to solve this question please .......
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The Given Linear Equation Has Been Solved By Elimination Method
Ultimately, we get, x=2 ; y=1
Ultimately, we get, x=2 ; y=1
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Answered by
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Answer:
Step-by-step explanation:
41x+53y=135------------ (1)
53x+41y=147-------------(2)
by elimination method,
multiply 41 in eq.(1) and multiply 53 in eq.(2),
(41x+53y=135)×41
(53x+41y=147)×53
1681x+2173y=5535
2809x+2173y=7791
- - -
__________________(by subtracting)
-1128x = -2256. (2173y-2173y cancelled)
x = -2256/-1128(- and - is cancelled
x = 2
put the value of x in eq. (2),
53x+41y=147
53×2+41y=147
106+41y=147
41y=147-106
41y=41
y=41/41
y=1
so the value of x=2
y=1
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