Question

42) A box contains 8 red balls, 12 blue balls, and 10 white ball.
Find the probability of
a)
Red and white ball
b)
Blue and Red ball.​

Answer 1

Answer:

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Step-by-step explanation:

n(s) = 8 + 12 + 10 = 30

n(red) = 8

n(blue) = 12

n(white) = 10

a) P(A) = n(red and white) / n(s) = (8+10)/30 = 18/30 = 3/5

b) P(B) = n(blue and red) / n(s) = (12+8)/30 = 20/30 = 2/3

(a) 3/5

(b) 2/3

Answer 2

Answer:

a) 18/30

b) 20/30

I hope this is correct