42. A car, starting from rest, has a constant acceleration for a time interval , during which it covers a distances S In the next time intervalis the car has a constant retardation a, and comes to rest after covering a distance szin time to Which of the following relations is!! .Spam=10 answer report!!!
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Step-by-step explanation:
Distance traveled in t
0
seconds
S
1
=0×t
0
+
2
1
αt
2
(u=0 which is at rest)
Final velocity after t
0
seconds,
V
s
=0+αt
0
Final velocity after applying retardation β=0
Initial velocity =final velocity after t
0
seconds
0=(V
s
)
2
−2β(s
2
) (s
2
is the distance traveled after β retardation)
s
2
=
2β
(V
s
)
2
s
2
=
2β
α
2
t
0
2
s
1
+s
2
=
2
1
αt
0
2
(α+
β
α
)
=
2β
αt
0
2
(α+β)
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