Question

42. A force of 10 N acts on a body of mass 20 kg fc
10 seconds. The change in its momentum is
(1) 50 kg-m/s
(2) 100 kg-m/s
(3) 300 kg-m/s
(4) 1000 kg-m/s
NLOO
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Answer 1

Answer:

100 kgms^-1

Explanation:

f=ma

from here a =0.5 ms2

then change in momentum

= m(v-u)

from 1st eqn of motion

v-u=at

m(v-u)=20*10*0.5

=100 kgm/s