Question

42. A taut string fixed at both ends vibrates in nth
overtone. The separation between adjacent node and
antinode is equal to 'd'. Then string length is
1) 2d(n+1) 2) d(n+1) 3) 2dn 4) 2d(n-1)​

Answer 1

Answer:

For a taut string between two ends:

n

th

overtone=(n+1)harmonic

n

th

overtone=(n+1)harmonic

2

(n+1)

λ=L..............(L=lengthofstring).............(1)

Distance between node and antinode is given by

4

λ

which is equal to "d" according to the question. (

4

λ

=dorλ=4d)

Substituting the value of d in equation (1)

2

(n+1)4d

=L

(n+1)2d=L

Explanation:

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