Question

42) Amol is an inspection incharge rejects 0.08% of the
items as defective. How many will he examine to
reject 4 ?
A 3200
B. 5000
C. 4000
D. 4500​

Answer 1

Given : Amol is an inspection incharge rejects 0.08% of the items as defective.

To Find : How many will he examine to reject 4  

A. 3200

B. 5000

C. 4000

D. 4500​

Solution:

let say Item inspected  =  N

Rejected = 0.08 %

= (0.08/100)N

= 8N/10000

Rejected  = 4

=> 8N/10000 = 4

=> 8N = 40000

=> N = 5000

5000 items will be examined

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Answer 2

$\huge \: \: ☠︎ \: \cal \colorbox{tan}{ANSWER} \: ☠︎$

$\sf \color{royalblue}{Question} \rightarrow$

Amol is an inspection incharge rejects 0.08% of the items as defective. How many will he examine to reject 4 ?

$\sf \color{royalblue}{Answer} \rightarrow$

$\sf \: Let \: the \: items \: inspected \: be \bf \: x.$

$\sf \: Rejected = 0.08 \%$

$\sf= ( \frac{0.08}{100} ) x$

$\sf = \frac{0.08x}{10000}$

$\sf \: Rejected = 4$

$\sf \: \frac{8x}{10000} = 4$

$\sf \: 8x \: = 40000$

$\sf \: x = \frac{40000}{8}$

$\bf \: x = 50000$