Question

42) Calculate the empirical and molecular formula of a compound containing 76.6%
carbon, 6.38 % hydrogen and rest oxygen its vapour density is 47.​

Answer 1

Explanation:

Empirical formula = C6H6 O Va-pour density 47 ∴ Molecular mass = 2 x vapor density = 2 x 47 = 94 Molecular formula Empirical formula x n Molecular mass x n n = (Molecular mass) / (Empirical formula mass) = 94/94 = 1 ∴ Molecular formula = C6H6O