Question

42. Calculate the Equivalent resistance of the circuit. ​

Answer 1

For resisters in parallel

1/Req = 1/4+1/12 = 4/12 = 1/3

Req = 3

For resisters in series

Req = 3+8 =11

Answer 2

Answer:

The equivalent resistance of the circuit will be 11 Ω.

Explanation:

Resistances can be connected in two different ways in a circuit. The series and parallel connection.

The effective resistance in a circuit if the resistances are connected in a series manner will be,

R = R₁ + R₂

The effective resistance in a circuit if the resistances are connected in a parallel manner will be,

1/R = 1/R₁ + 1/R₂

In the given circuit the resistances of 4 Ω and 12 Ω are connected in a parallel method. So their effective resistance will be:

1/R = 1/4 + 1/12

1/R = (12 + 4) / (12 × 4)

1/R = 16 / 48

R = 48 / 16

R = 3 Ω

This effective resistance of 3 Ω is in a series connection with the 8 Ω resistance.

∴ R = 3 + 8 = 11 Ω