42. Find volume of oxygen gas in 800g CaCO3 ?
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42. Find volume of oxygen gas in 800g CaCO3 ?
Explanation:
Heating of CaCO3 is carried out according to following reaction : CaCO3 + CaO + CO2 Molar mass of CaCO3 = 100 g Molar mass of CaO = 56 g Molar mass of CO2 = 44 g According to reaction , 1 mole of CaCO3 produces 1 mole of CO2 100 grams of CaCO3 produces 44 grams of CO2 50 g of CaCO3 produces ( 44/100 ) x 50 = 22 grams Mass of CO2 produced = 22/44 = 0.5 Volume of CO2 = 22.4 x 0.5 moles = 11.2 Liters
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