Question

42. If p=x/y + y/x and q=x/y - y/x show that p^4 + q^4 - 2p^2^2 = 16​

Answer 1

Answer:

$pq-^4 =16$

Step-by-step e

$p^{4} +q^{4} -2 p^{2}^{2} =16$

$-p^4 +q^{4}=16$