Question

42) The momentum of a particle having a de-Broglie
wavelength of 10-17 m is
(Given h= 6.625 x 10-34m)
a) 3.3125 x 107 kg ms!
b) 26.5 x 107 kg m si
c) 6.625 x 10-17 kg m s -1
d) 13.25 x 10-17 kg ms!​

Answer 1

Answer:

will ans will u shortly pls wait

Answer 2

Answer:

$p = 6.625 \times 10 {}^{ - 34} \div {10}^{ - 17}$

Explanation:

use formula

lambda=h/p

lambda is wavelength and p is momentum