42. Two moles of ammonia is introduced in a evacuated
500 ml vessel at high temperature. The
decomposition readion is:
2NH,10 N,(g) + 3H2(g)
At the equilibrium NH, becomes 1 mole then the
would be:
(1) 0.42 (2) 6.75 (3) 1.7 (4) 1.5
Answers
Answered by
4
Answer:
2NH
3
(g)⇌N
2
(g)+3H
2
(g)
atequil.2−2xx3x
Amount of NH
3
left is 1 mole
2−2x=1
x=0.5
K
c
=
[NH
3
]
[N
2
][H
2
]
3
=
1
(0.5)(1.5)
3
=1.7
Explanation:
hope you got it
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