Question

42. x ^ 2 + 5x - (a ^ 2 + a - 6) = 0

pls solve this question​

Answer 1

Answer:

x² + 5x - (a²+ a - 6) = 0

x²+5x-(a²+3a-2a-6)=0

x²+5x-(a(a+3)-2(a+3))=0

x²+5x-(a+3)(a-2)=0

x²+[(a+3)-(a-2)]x-(a+3)(a-2)=0

x²+(a+3)x-(a-2)x-(a+3)(a-2)=O

x[x+(a+3)]-(a-2)[x+(a+3)]=0

[x+(a+3)][x-(a-2)]=0

[x+(a+3)]=0 or [x-(a-2)]=0

x=-(a+3) or x=(a-2)

Answer 2

x² + 5x - (a²+ a - 6) = 0

x²+5x-(a²+3a-2a-6)=0

x²+5x-(a(a+3)-2(a+3))=0

x²+5x-(a+3)(a-2)=0

x²+[(a+3)-(a-2)]x-(a+3)(a-2)=0

x²+(a+3)x-(a-2)x-(a+3)(a-2)=O

x[x+(a+3)]-(a-2)[x+(a+3)]=0

[x+(a+3)][x-(a-2)]=0

[x+(a+3)]=0 or [x-(a-2)]=0

x=-(a+3) or x=(a-2)