Question

42. x² + 5x- (a² + a-6) = 0​

Answer 1

Step-by-step explanation:

x² + 5x - (a² + a - 6 ) = 0

x² + 5x - ( a² + 3a - 2a - 6 ) = 0

x² + 5x - [a(a + 3) -2(a + 3)] = 0

x² + 5x - ( a - 2 ) ( a + 3 ) = 0

x² + (a + 3)x - (a - 2)x - (a - 2) (a + 3) = 0

x [ x + (a + 3)] - (a -2) [x + ( a + 3)] = 0

[ ( x + (a + 3) ( x - ( a - 2) ] = 0

x = - (a + 3) x = ( a - 2 )

x = - (a + 3) , ( a - 2)