Question

420 articles are divided among A,B and C such that A geta three times. of B and B gets five times of C . find the number of articles received by B​

Answer 1

USING LINEAR EQUATIONS

Answer:

C gets 20 articles so B will get 20 × 5 = 100 articles

Step-by-step explanation:

Let C be x

So B will be 5x and A be 15x

According to Question

15x + 5x + x = 420

21x = 420

x = 420 ÷ 21

x = 20

Answer 2

Answer:

No of articles received by B = 5x = 5×20 = 100

Step-by-step explanation:

Total number of articles = 420

Let the number of articles C gets be x

Then the number of articles B gets = Five times the number of articles C gets = 5x

The number of articles A gets = 3 times the number of articles B gets

= 3×5x = 15x

Total number of articles = No of Articles A gets + No of articles B gets +No of articles C gets

420 = 15x +5x+x

420 = 21x

x = $\frac{420}{21}$ = 20

x =  No of articles c gets = 20

∴No of articles received by B = 5x = 5×20 = 100

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