Question

420 J of energy supplied to 10 g of H2O The raise in it's temperature is

Answer 1

Given :

Mass of water = 10g

Supplied heat energy = 420J

To Find :

Raise in the temperature of water.

Solution :

❖ Specific heat capacity of substance is defined as the heat required to increase temperature of 1g substance by 1°C.

Formula : s = Q / m ∆T

• s denotes specific heat capacity
• Q denotes supplied energy
• m denotes mass
• ∆T denotes change in temperature

Specific heat capacity of water is 4.2 J/g °C

By substituting the given values;

➙ Q = m s ∆T

➙ 420 = 10 × 4.2 × ∆T

➙ ∆T = 42/4.2

➙ ∆T = 10°C

Knowledge BoosteR :

• Specific heat capacity of water is very large. This is the reason why water is used as a coolant in automobile radiators as well as a heater in hot water bags.
• Determination of specific heat or latent heat of a substance using principle of calorimetry is good enough provided there is no loss of heat$.$

Answer 2

$\huge{\underline{\underline {\mathtt{\purple{Hlw}\pink{Mate}}}}}$

$\Large\bold\blue{Given:}$

Mass of $H_2O$= 10g

Supplied heat energy = 420J

$\Large\bold\blue{To\:Find:}$

Raise in the temperature of water.

$\Large\bold\blue{Solution:}$

$\Large\fbox\pink{Formula\: s\: = \: Q / m ∆T}$

Let,

s = specific heat capacity

Q = supplied energy

m = mass

∆T= change in temperature

Specific heat capacity of $H_2O$ is 4.2 J/g °C

Substituting the given values,

➙ Q = m s ∆T

➙ 420 = 10 × 4.2 × ∆T

➙ ∆T = 42/4.2

➙ ∆T = 10°C

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