Question

420 joules energy supply to 10 grams water will raise its temperature by

Answer 1

hey mate here is your answer..^^

q = mC∆T 

420J = (10g)(4.184J/g-deg)(∆T)
 
∆T = 420/(10)(4.184)
= 10 degrees centrigrade

Answer 2

Hello there,

● Answer-

∆T = +10 °C

● Explaination-

# Given-

Q = 420 J = 100 cal

m = 10 g

c = 1 cal/gm°C

# Solution-

Energy supplied to the water is given by-

Q = mc∆T

100 = 10 × 1 × ∆T

∆T = 100 / 10

∆T = 10 °C

Therefore, heating the water will increase its temperature by 10 °C.

Hope it helps...