Question

420 mL of a gas at 25.0°C 1S compressed to 210 mL. What is the temperature of the gas after
compression?
(a) 12.5°C
(b) 149 K
(c) 273 K
(d) 0°C​

Answer 1

Answer:

ans is 149K

By applying the gas law

Answer 2

Answer:

The temperature of the gas after compression is 149K.i.e.option(b).

Explanation:

From the Charles law we know that the volume of a gas directly proportional to its absolute temperature i.e.

$V\propto T$        (1)

Equation (1) can also be written as,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$        (2)

From the question we have,

V₁=420mL

T₁=25+273=298K

V₂=210mL

By substituting the required values in equation (2) we get;

$\frac{420}{298}=\frac{210}{T_2}$

$T_2=\frac{210\times 298}{420}$

$T_2=149K$

Hence, the temperature of the gas after compression is 149K.i.e.option (b).