Question

42asquare-8a (a-1)-7a (1+5a) +a (a-1) equals

Answer 1

Given expression,
42a²-8a(a-1)-7a(1+5a)+a(a-1)
=42a²-8a²+8a-7a-35a²+a²-a
=42a²-8a²-35a²+a²+8a-7a-a
=42a²+a²-8a²-35a²+8a-8a
=43a²-43a²+8a-8a
=0+0
=0 

Answer 2

Step-by-step explanation:

Given,

42a²-8a(a-1)-7a(1+5a)+a(a-1)

=42a²-8a²+8a-7a-35a²+a²-a

=42a²+a²-8a²-35a²+8a-7a-a

=43a²-43a²+a-a

=43a²-43a²

=0