42y-4x=10,3x-2y=1 solve by substitution method
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Answer:
42y -4x =10
y = 10+4x/42 - - - - (1)
3x -2y =1
3x - 2(10+4x)/42 = 1
3x -10-4x /21 = 1
53-4x /21 = 1
53-4x = 21
-4x = 21-53
-4x = -32
x = 32/4=8
y = 10+4x / 42 = 10+ 4(8)/42= 10+32/42 = 42/42 = 1
•°•x=8, y = 1
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