Question

43 0.2 gm of a metal chloride on treatment with excess of AgNO3 solution yields 0.50 gm of AgCl. The
arity (4) 5 times of its molarity
equivalent mass of that metal is
(1) 21.9
(2) 20.04
(3) 40.08
(4) 43.8​

Answer 1

Explanation:

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Avogadro's number is 6.023×10

23

1.2×10

22

ions corresponds to

6.023×10

23

1.2×10

22

=0.02 moles.

100 mL of 0.1M solution of CoCl

3

.6H

2

O corresponds to

1000mL/L

100mL

×0.1M=0.01moles.

0.01 moles of CoCl

3

.6H

2

O reacts with excess AgNO

3

to form 0.02 moles of AgCl precipitate, which means 0.01 moles of Ag

+

and 0.01 moles of Cl

−

ions.

Thus, from one molecule of CoCl

3

.6H

2

O, one chlorine atom is displaced. Hence, the complex is

[Co(H

2

O)

5

Cl]Cl

2

.H

2

O as number of chloride ion outside co-ordination sphere should be one.

Hence, the option (3) is the correct answer.

Answer 2

Avogadro's number is 6.023×10

23

1.2×10

22

ions corresponds to

6.023×10

23

1.2×10

22

=0.02 moles.

100 mL of 0.1M solution of CoCl

3

.6H

2

O corresponds to

1000mL/L

100mL

×0.1M=0.01moles.

0.01 moles of CoCl

3

.6H

2

O reacts with excess AgNO

3

to form 0.02 moles of AgCl precipitate, which means 0.01 moles of Ag

+

and 0.01 moles of Cl

−

ions.

Thus, from one molecule of CoCl

3

.6H

2

O, one chlorine atom is displaced. Hence, the complex is

[Co(H

2

O)

5

Cl]Cl

2

.H

2

O as number of chloride ion outside co-ordination sphere should be one.

Hence, the option (3) is the correct answer.