Question

43. 0.5 mole of a gas is heated from 27°C to 327°C at
constant pressure. Find out the heat given to the gas
and increase in its internal energy. Fit gas Co=7
cal/mol-"C and C=5 cal/mol-°C.
Ans. 420 cal, 300 cal​

Answer 1

Answer:

Heat given to the gas is 1050 Cal and its increase in internal energy is 750 Cal.

Explanation:

As we know that heat given to the gas at constant pressure is given by the formula

$Q = nC_p\Delta T$

here we have

$n = 0.5$

$C_p = 7$

$\Delta T = 327 - 27 = 300 ^oC$

so we will have

$Q = 0.5(7)(300)$

$Q = 1050 Cal$

Now for change in internal energy we know that the formula is given as

$\Delta U = nC_v\Delta T$

$\Delta U = 0.5(5)(327 - 27)$

$\Delta U = 750 Cal$

#Learn

Topic : Thermodynamics

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