Question

43. A car moving on straight path, travels first half of
distance with speed 20 m/s and another half of
distance with speed 40 m/s, then average speed
of the joumey is
​

Answer 1

Answer:

80/3 m/s

Explanation:

Let the total distance be x

Time taken for first half = Distance/Speed = x/2 ÷ 20 = x/2 ×1/20 = x/40

Time taken for second half = x/2 ÷ 40 = x/80

Total time = x/40 + x/80 = 3x/80

Avg. Speed = Total distance/ Total time = x÷ 3x/80 = 80/3 m/s