43. A force acts on a moving body of mass 50 kg and changes its velocity from
5 m/s to 10 m/s. The amount of work done by the force is :
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Answer:
W=1875J
Step-by-step explanation:
m=50kg
u=5m/s
v=10m/s
W=?
W=FS
W=m×a×(ut+1/2at²)
W=50×(v-u/t)(t)(u+1/2at)
W=50×(10-5) (5+1/2×10-5/t×t)
W=50×5(5+1/2×5)
W=50×5(5+5/2)
W=50×5(15/2)
W=50×75/2
W=25×75
W=1875J
hope this helps you
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