Question

43. A ladder of length 5m is placed
against a wall 4m long. Find the
distance of foot of the ladder from
the foot of the wall. [4]
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Answer 1

Answer:

by Pythagoras theorem

( H ) square = (A) Square + ( B) square

we have to take out base

(B) square = (H) square - (A) square

(B) square = (5) square - (4) square

(B) square = 25-16

(B) square = 9

B= √9

B=3

distance of the foot of the ladder = 3

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