Question

43) Find the sum of the series 1+2 +3 + ... + 100.
A.5000
3.5050
0.4050
0.4000​

Answer 1

answer 5050 sum of the series

Answer 2

Answer:

sn=n/2(2a+[n-1]d)

Explanation:

s100=100/2(2×1+[100-1]×1

=50(2+99)=101×50

5050

or

sn =n^2+n/2

=100^2+100/2

=10000+100/2

=10100/2

=5050