Question

43. Find two numbers whose sum is 27 and product is 182.

PLS HELP ME TO SOLVE IT BY DISCRIMINATION METHOD​

Answer 1

Answer:

Given that,

$\sf\pink{In\: that \:numbers,}$

$\sf\blue{let \:one \:of \:the\: numbers \:be \:‘x’}$

$\sf\red{Another\: number = (27 – x)}$

$\sf\orange{Their \:Product = 182}$

Now,

$\sf \pink \implies \purple{x (27 - x) = 182}$

Then,

$\sf \blue \implies \green{27x – x2 = 182 -x2 + 27x – 182 = 0}$

$\sf \red \implies \orange {x2 – 27x + 182 = 0}$

$\sf \green \implies \blue{ x2 – 14x – 13x + 182 = 0}$

$\sf \purple \implies \pink {x(x – 14) – 13(x – 14) = 0 }$

$\sf \green \implies \blue{(x – 14) (x – 13) = 0}$

$\sf \red{If \: x – 14 = 0, \: then \: x = 14}$

$\sf \purple{If \: x – 13 = 0, \: then \: x = 13}$

$\sf\blue \therefore\green {x = 14 \: or \: x = 13}$

$\sf \red\implies \orange{the \: numbers \: are \: 14 \: and \: 13}$

Answer 2

Answer:

Given that,

$\sf\pink{In\: that \:numbers,}$

$\sf\blue{let \:one \:of \:the\: numbers \:be \:‘x’}$

$\sf\red{Another\: number = (27 – x)}$

$\sf\orange{Their \:Product = 182}$

Now,

$\sf \pink \implies \purple{x (27 - x) = 182}$

Then,

$\sf \blue \implies \green{27x – x2 = 182 -x2 + 27x – 182 = 0}$

$\sf \red \implies \orange {x2 – 27x + 182 = 0}$

$\sf \green \implies \blue{ x2 – 14x – 13x + 182 = 0}$

$\sf \purple \implies \pink {x(x – 14) – 13(x – 14) = 0 }$

$\sf \green \implies \blue{(x – 14) (x – 13) = 0}$

$\sf \red{If \: x – 14 = 0, \: then \: x = 14}$

$\sf \purple{If \: x – 13 = 0, \: then \: x = 13}$

$\sf\blue \therefore\green {x = 14 \: or \: x = 13}$

$\sf \red\implies \orange{the \: numbers \: are \: 14 \: and \: 13}$