Question

43) Four numbers are in AP. The sum of extremes is 10 and the product of the means
is 24. Find the numbers.
​

Answer 1

Answer:

Let a,ar,ar

2

,ar

3

be 4 terms

Sum of Extreme a+ar

3

=112

sum of Middle ar+ar

2

=48

⟹

r+r

2

1+r

3

=

3

7

⟹3r

3

−7r

2

−7r+3=0

⟹r=3,−1,

3

1

where −1 doesnot fit to solution..

Let r=3

a(3)+a(3)

2

=48⟹a=4

so the 4 terms are 4,12,36,108

Step-by-step explanation:

hope this will help you