Question

43. From a right circular cylinder of radius 10 cm and height 21 cm, a right circular cone of same base-radius is removed. If the volume of the remaining portion is 4400 cm3, then the height of the removed cone (taking = ) is

Answer 1

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Answer 2

The height of removed cone is 21 cm

Step-by-step explanation:

Let the height of cone be h

Radius of cylinder = 10 cm

Height of cylinder = 21 cm

Radius of cone = 10 cm

A right circular cone of same base-radius is removed. So,the volume of the remaining portion is 4400 cm3

So, Volume of Remaining = Volume of cylinder - Volume of cone

$4400=\pi r^2h-\frac{1}{3} \pi r^2 H\\4400=\frac{22}{7}(10)^2(21-\frac{1}{3}H)\\\frac{4400 \times 7}{22 \times 10^2}=21-\frac{1}{3}H\\14=21-\frac{1}{3}H\\\frac{1}{3}H=21-14\\H=7 \times 3 \\H=21 cm$

Hence The height of removed cone is 21 cm

#learn more :

Radius and height of a right circular cone and that of a right circular cylinder are respectively,equal.if the volume of the cylinder is 120 cm3 ,then the volume of the cone is equal to:

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