Question

43. If the equation x² – (2 + m)x + (-m² – 4m – 4) = 0 has coincident roots, then​

Answer 1

Answer:

Step-by-step explanation:

If equation ax  

2

+bx+c=0, then the roots are equal (coincident) when b  

2

−4ac=0.

In equation x  

2

−(2+m)+1(m  

2

−4m+4)=0

The a=1  b=−(2+m)   c=m  

2

−4m+4

Thenb  

2

−4ac={(−(2+m))}  

2

−4(1)(m  

2

−4m+4)=0

⇒m  

2

+4m+4−4m  

2

+16m−16=0

⇒−3m  

2

+20m−12=0⇒−3m  

2

+18m+2m+6=0

−3m(m−6)+2(m−6)=0⇒(−3m+2)(m−6)=0

If -3m+2=0 then m=  

3

2

​  

 

If m−6=0 then m=6

Answer 2

Answer:

m=6

Step-by-step explanation:

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