| | 43. If x=3+33 +33, thеn thе vаluе оf x3 - 9х2 + 18х - 6 - 1) 12 2) 8 3) 6 4) 4 С C 1 О 2 О O 3 О 4
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→bx=3+3⅓+3⅔
or,(x−3)=3⅓+3⅔
Therefore,
(x−3)3=(3⅓+3⅔)3
or,x3−27−9x2+27x=3+9+3×3(3⅓+3⅔)
or,x3−27−9x2+27x=12+9(x−3)[Puttingthevalue(x−3)=(3⅓+3⅔)]
or,x3−27−9x2+27x=12+9x−27
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