43. The distance moved by car P during the time interval in which they cross each other is(1) 40 m(2) 10 m(3) 220 m(4)36 m
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The distance moved by car P during the time interval in which they cross each other is
Vp will be 10 m/s
Vq will be 15 m/s
Length of each car is 5m
The cars cross each other at time 5 o ,clock.
Just after crossing P covered (x + 5) m and Q covered (95-x) m
Vp = distance / time = x+5/t
Vq = 95-x / t
So x+5/10 = 95-x / 15
x = 35m
So the car would have covered 40 m.
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