Question

43. ​The figure shows the face and interface temperature of a composite slab containing of four layers of two materials having identical thickness. Under steady state condition, find the value of temperature θ.




(1) 5°C(2) 10°C(3) -15°C(4) 15°C

Answer 1

The value of temperature is θ = 5°C

Explanation:

In steady state heat current will be same.

i = ( dH / dt )4k . (dH /dt) 2k = ( dH / dt )k

[ dH /dt = -KAΔT/i]

(dH /dt )k = (4k)A(40 - 35)/i ..... (1)

( dH / dt )4k = K(25 - θ) / 1 ......(2)

On solving equation (1) and(2) it gives

θ = 5°C

Thus the value of temperature is θ = 5°C

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