Question

43. The greatest six digit number which is exactly divisible by 4238 is
tennetiraj please help for this ans​

Answer 1

Step-by-step explanation:

Given :-

The greatest six digit number

To find :-

Find the greatest six digit number which is exactly divisible by 4238 ?

Solution :-

We know that

The greatest six digit number = 9,99,999

The divisor = 4238

To get the required number

We have to divide 9,99,999 by 4238

4238)999999(235

8476

_______

15239

12714

_________

2525 9

21 1 9 0

__________

40 6 9

____________

So we have to Subtract 4069 from 999999 to get the number =

999999-4069 = 995930

or

The greatest six digit number = 9,99,999

The divisor = 4238

We use Euclids Division Lemma

Write it as a= bq+r

Where a = 999999 b = 4238

999999 = 4238×235 + 4069

So the required number is exactly divisible by 4238

It must be a multiple of 4238

So the remainder must be 0

So here remainder = 4069

So we can write it

4238×235 = 999999-4069

4238×235 = 995930

So required number = 995930

Answer:-

The six digit greatest number which is exactly divisible by 4238 is 995930

Used formulae:-

Euclids Division Lemma:-

For any two positive integers a and b there exist two positive integers q and r satisfying a = bq+r , 0≤r<b.