Math, asked by jangirpawan1998, 10 months ago

43.
Two mobile phones are sold at Rs. 6000 each.
The first mobile is sold at 20% profit and the
other one at 25% loss. What is the percent-|
age of loss or profit incurred during the deal?!
दो मोबाईल फोन 6000 रूपये प्रति फोन के मूल्य |
पर बेचे जाते हैं प्रथम मोबाईल को 20 प्रतिशत लाभ
पर बेचा जाता है और द्वितीय मोबाईल को 25
प्रतिशत हानि पर बेचा जाता है। सौदे के दौरान हुए
लाभ अथवा हानि का प्रतिशत क्या होगा?
(A)7.7% loss (B) 8.3 loss
(C)9% loss
(D) 2% profit

Answers

Answered by panesarh989
2

Answer:

Let there be two mobiles X and Y, for X,

S.P= 6000 (Given)

Profit%=20%

Then CP= (6000x100)/120=5000

Similiarly, for Mobile Y

S.P= 6000 (Given)

Loss%=25%

Then CP= (6000x100)/75= 8000

Total Cost Price, i.e., Total CP= 8000+5000=13000

Total Selling Price, i.e., Total SP= 6000+6000=12000

Since S.P< C.P loss has occured.

Also,

Loss% = [(C.P-SP)/CP]x100

Thus,

Loss%=(1000/13000)x100=7.692%

Answered by ferozpurwale
0

Answer:

Let there be two mobiles X and Y, for X,

S.P= 6000 (Given)

Profit%=20%

Then CP= (6000x100)/120=5000

Similiarly, for Mobile Y

S.P= 6000 (Given)

Loss%=25%

Then CP= (6000x100)/75= 8000

Total Cost Price, i.e., Total CP= 8000+5000=13000

Total Selling Price, i.e., Total SP= 6000+6000=12000

Since S.P< C.P loss has occured.

Also,

Loss% = [(C.P-SP)/CP]x100

Thus,

Loss%=(1000/13000)x100=7.692%

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