Question

43062 का 10 की घातों में विस्तारित रूप निम्न में कौन है?
(1) 4 x 103 + 3 + 3 x 102 + 0 + 62
(2)4x104 +3x103 + 0+ 6x10+2
(3) 4x105 +3x104 +0+6x100+2x10+ 0
(4)4x106 +3x105 +0+ 6x1000+ 2x100​

Answer 1

Answer:

Correct option is

A

9991

103×97=(100+3)(100−3)

Using, a

2

−b

2

=(a+b)(a−b)

=(100)

2

−(3)

2

=10000−9

=9991

Step-by-step explanation:

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Answer 2

Answer:

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