432^412×499^431 find unit digit
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Answer:
(432)412 × (499)431
Taking unit digits
⇒ 2412 × 9431
As we know unit digit of 21 = 2, 22 = 4, 23 = 8, 24 = 6
⇒ 24(103) × 9431
⇒ 6 × 9
⇒ 54
∴ The unit digit of (432)412 × (499)431 is 4.
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