Question

44 х - Х - 2 factorise​

Answer 1

Answer:we have,

=> 44x^2 - x - 3

=> 44x^2 - 12x + 11x - 3

=> 4x(11x-3) + (11x-3)

=> (11x-3)(4x+1)

thus the factorised form of

44x^2-x-3 is (11x-3)(4x+1).

note;

if we want to find the zeros of the given polynomial, then we would equate its factors equal to zero.

here , we have the factorised form of polynomial as: (11x-3)(4x+1)

thus to get it's zeros,we have,

=> (11x-3)(4x+1)=0

ie, either (11x-3)=0 or (4x+1)=0

thus, the zeros of the polynomial would be: x=3/11 or -1/4

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