Question

44.8 litres of H2, and 67.2 litres of
02, are mixed at STP. The weight
of the mixture is
1) 112g
2) 22.4g
3) 100g 4) 44.8g​

Answer 1

Answer:

The answer is = 100 g

Explanation:

44.8 litres = 2 moles of H2

==> No. of moles = volume(in litres) / 22.4 litres

No. of moles of H2 = 44.8 litres / 22.4 litres.

No. of moles of H2 = 2 moles mass of H2 = 4 g

Similarly moles of O2 = 67.2 /22.4

Moles of O2 = 3 moles

Mass of O2 = 96 g

Total mass = 4g + 96g

= 100 g.

Answer 2

Answer:

• hfdduiknvzswwryyyyyh