Question

44.8L CH4 gas at STP = .........Grams.

Answer 1

Answer:

32g

Explanation:

Given volume=44.8L

Molecular mass = 12+ 4*1=16

let 'n' be no. of moles

n=given volume/22.4

n=44.8/22.4

n=2 moles

Also,

n=given mass/molecular mass

2=given mass/16

2*16=given mass

given mass=32g

Therefore ,32g is the mass of 44.8L of CH4 gas at STP