44. A coin is tossed three times. Find the probability of following events.
a) getting at least two heads
b) getting at most one head
c) getting more heads than tails with metho
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1
Answer:
Sample space: {
HHH,HTH,THH,TTH
HHT,HTT,THT,TTT
}
Total number of possible outcomes=8
(1) A getting at least two heads
P(A)=P(getting two heads)+P(getting 3 heads)
=
8
3
+
8
1
(using formula=P(event)=
Total no. of possible outcomes
No. of favourable outcomes
P(A)=
8
4
=
2
1
∴P(A)=
2
1
(2) B: getting exactly two heads
P(B)=3/8
(3) C: getting almost one head
P(C)=P(getting no head)+P(getting 1 head)
=
8
1
+
8
3
=
8
4
=
2
1
P(C)=
2
1
.
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