Question

44. a) The sum of the digits of a given two digit number is 5. If the
digits are reversed, the new number is reduced by 27. Find the
given number.

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Answer 1

Let 2 digit no be XY

X+ Y= 5...(1)

NOW if digit reversed new no is reduced by 27

YX= XY - 27

10 y + x = 10 x + Y -27

9y - 9x = -27

x - y= 3......(2)

(1)+(2)

2x = 8

x= 4

put x= 4 in x-y = 3

y= x-3 = 4-3 = 1

Given no is XY = 41

Answer 2

the two digits are x and 5-x

(x*10+(5-x))-((5-x)*10+x)=27

9x+5-50+9x=27

18x=18

x=1