44 g of cao is reacted with 28.4g of p4o10. the mass of calcium phosphate is obtained in a reaction is
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44 g of complent is phoyoty is called
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Answer:
given = 44g of CaO
28.4g of P₄O₁₀
to find = mass of calcium phosphate is obtained in a reaction.
solution =
6CaO + P₄O₁₀ ⇒ 2Ca₃ (PO₄)₂
now for moles of P₄O₁₀ = 28.4 / 28.4
P₄O₁₀ = 0.1mol
number of moles of CaO = 44.8/ 56
CaO = 0.8mol
we can conclude that 1 mole of P₄O₁₀ produce 2 mol ca3(PO₄)₂
0.1 mol P₄O₁₀produce 0.2mol Ca₃(PO₄)₂
mass of calcium phosphate is obtained in a reaction is MOLES X MOLAR MASS
∴ 0.2 X 310
∴ 62g
so, the mass of calcium phosphate is obtained in a reaction is 62g
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