44 g of sample on complete combustion gives 88 gm co2 and 36 gm h20
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Answer:
Explanation:
C2H4O . .............. 88 g of CO2 = 88 / 44 = 2 moles of CO2
that has 2 moles of C ........and
36 grams of H2O = 36 / 18 = 2 moles of H2O
that has 4 moles of H ..........as mass of sample is 44 grams
it must have 2 moles or 2 x12 =24 g of C , 4 moles or 4 x 1 = 4 grams of H and rest 16 grams must be 1 mole of O .....
.hence molecular formula of compound is C2H4O
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0
Explanation:
C2H4O is the answer।।।।।।।।
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